摘要
东农３０３（Ｓ．Ｔｕｂｅｒｏｓｕｍ）核型为：２＝４ｘ＝４８＝５×（４）＋５×（４）ＳＭ＋１×（４）ＳＴ＋１×［（２）ＳＴ＋（２）］，组型为：２ｎ＝４ｘ＝１１Ⅳ＋＋（１Ⅱ＋１Ⅱ）＝５Ｍ（Ｂ、Ｅ、Ｇ、Ｋ、Ｌ）＋５ＳＭ（Ａ、Ｃ、Ｄ、Ｈ、Ｊ）＋１ＳＴ（Ⅰ）＋１［（Ｔ＋ＳＴ）（Ｆ）］。Ｓ４－５－３－６－５－１－５０－（１０）（Ｓ．Ｔｕｂｅｒｏｓｕｍ）核型为：２ｎ＝４ｘ＝４８＝４×（４）Ｍ＋６×（４）ＳＭ＋１×（４）ＳＴ＋１×［（２）ＳＴ＋（２）Ｔ］，组型为：２ｎ＝４ｘ＝１１Ⅳ＋（１Ⅱ＋１Ⅱ）＝４Ｍ（Ｅ、Ｇ、Ｋ、Ｌ）＋６ＳＭ（Ａ、Ｂ、Ｃ，Ｄ、Ｈ、Ｊ）＋１ＳＴ（Ⅰ）＋１［（Ｔ＋ＳＴ）（Ｆ）］。Ａ组与Ｆ组带有髓体，两份供试材料的对应组中染色体略有分化，但基本一致。
Abstract The karyotype of cultivar NEA303 is 2n = 4x =48 = 5 × (4)M + 5 × (4)SM + 1 × (4)ST + 1 ×[(2)ST+ (2)T], and the genome is 2n=4x =11Ⅳ+ (1Ⅱ +1Ⅱ)=5M(B, E, G, K and L) + 5SM(A,C, D, H and J)+ 1ST(Ⅰ)+ 1[(T+ ST)=(F)]. The karyotype of a clone S4-5-3-6-5-1-50-(10) is 2n = 4x + 48=4 × (4)M + 6 × (4)SM + 1 × (4)ST+ 1 × [(2)ST+ (2)T], and the genome is 2n =4x= 11Ⅳ+ (1Ⅱ+ 1Ⅱ) =4M(E, G, K and L)+6SM(A, B, C, D, H and J)+ 1ST(Ⅰ)+1[T+ST)(F)].The chromosomes in A and F group have satellite. the chromosomes of corresponding group in the two plant materials studied are differentiated to some extent, but basically are the same.
出处
《马铃薯杂志》
1994年第2期81-84,共4页
Chinese Potato Journal
