摘要
在给定了应当接收的次品率上界p_0,应当拒绝的次品率下界p_1,犯两类错误的允许概率α与β,子总体次品率p的经验分布函数F(p)后,Bayes两次抽检方案可用计算机求得,本文给出了求解公式与计算实例。
Given p0, p1, α, β and F(p), we can give the Bayes plan of double sampling inspection which has the smallest average sample size by computer, where p0 is the upper bound of the rate of rejection to be accepted, p1 the lower one to be refused, α the probability of committing a type 1 error, β the probability of committing a type 2 error, and F(p) the experimental distribution function of the rate of rejection p of the subpopulation.In this paper, we work out the abgve solution and apply to Chinese silkworms.
出处
《高校应用数学学报（A辑）》
CSCD
北大核心
1989年第1期134-136,共3页
Applied Mathematics A Journal of Chinese Universities(Ser.A)
