摘要
在鲑鱼胚胎细胞(CHSE)培养中,低乳酸浓度(1.1～6.14mmol/L,相应渗透压为644～673kPa)对细胞生长无明显影响,主要的代谢特征基本不变;在高乳酸浓度(13.1～41.58mmol/L,相应渗透压为701～944kPa)下培养,细胞生长受到抑制,代谢发生明显变化。乳酸对CHSE细胞生长的抑制作用主要由乳酸导致培养基pH下降和渗透压增加引起。在CHSE细胞批培养中,维持正常的pH,7mmol/L的乳酸浓度,不会明显抑制CHSE细胞的生长。
Growth and main metabolism features of chinook salmon embryo (CHSE) cells were not affected at 1.1-6.14 mmol/L of lactate, corresponding to medium osmotic pressure of 644-673 kPa. Higher lactate concentrations such as 13.1-41.58 mmol/L, corresponding to medium osmotic pressure of 701-944 kPa, inhibited CHSE cell growth and changed their metabolism. Inhibition of (CHSE) cell growth by lactate was mainly caused by the decline of pH and the increase of osmotic pressure in medium. CHSE cells could bear the lactate level as high as 7 mmol/L and grow regularly under a stable and neutral pH condition.
出处
《华东理工大学学报（自然科学版）》
EI
CAS
CSCD
北大核心
2005年第3期290-295,共6页
Journal of East China University of Science and Technology
基金
863青年基金项目(2001AA628010)
