摘要
目的:探讨STAT3在双酚A促乳腺癌MCF-7细胞增殖中的作用,为研究双酚A诱导乳腺癌的确切机制提供依据。方法:采用Western blot检测双酚A处理乳腺癌MCF-7细胞24 h和48 h后STAT3的表达情况,采用MTT法检测RNA干扰技术抑制STAT3后双酚A对乳腺癌细胞增殖的影响。结果:Western blot结果表明,STAT3在1μM双酚A作用48 h后其诱导表达最明显(P<0.05);通过对照研究筛选出有效的干扰片段,能显著抑制STAT3基因的表达,当干扰片段抑制了STAT3基因表达后,双酚A未能抑制STAT3的MCF-7细胞发生增殖效应(P>0.05)。结论:在双酚A诱导乳腺癌细胞的增殖作用中,STAT3的活化和活化后的信号传导是非常重要的一个环节。
Objective ： To explore the effect of STAT3 in promotion of proliferation of breast cancer cells with bisphenol A, and research the exact machanism of breast cancer induced by bisphenol A. Methods： Western blot was used to detect the expressions of STAT3 at 24 and 48 hours after treating breast cancer MCF - 7 cells with bisphenol A, MTT method was used to detect the effect of bisphenol A on proliferation of breast cells after suppressing STAT3 with RNA interfering technique. Results： The results of Western blot showed that the inducing effect of STAT3 after treated with 1 μM bisphenol A for 48 hours was the most obvious （ P 〈 0. 05 ） ; a case - control study was performed to screen out effective interfering fragments, which suppressed the expression of STAT3 gene significantly, when interfering fragments suppressed expression of STAT3 gene, bisphenol A didnl suppress the proliferative effect of STAT3 on breast cancer MCF - 7 cells （ P 〉 0. 05 ） . Conclusion ： The activation of STAT3 and signal transduction after activation is a very important link in proliferative effect of breast cancer cells induced by bisphenol A.
出处
《中国妇幼保健》
CAS
北大核心
2013年第17期2784-2787,共4页
Maternal and Child Health Care of China
基金
吉林省科技厅资助项目〔201105094〕
