摘要
设p是奇素数,证明了当p=6(4s+1)+1,其中s是非负整数时,方程x3-1=2py2仅有整数解(x,y)=(1,0);当p=6(4s+2)+1,其中s是非负整数时,方程x3+1=2py2仅有整数解(x,y)=(-1,0).
Let p be an odd prime, and this paper proves the following : if p = 6 (4s + 2) + 1, where s is a nonnegatire integer, then the equation x3 - 1 =2py2 has only integer solution (x,y) = ( 1,0) ; ifp =6(4s +2) + 1, where s is a nonnegative integer, then the equation x3 + 1 = 2py2 has only integer solution (x,y) = ( -1,0).
出处
《云南民族大学学报(自然科学版)》
CAS
2012年第6期438-441,共4页
Journal of Yunnan Minzu University:Natural Sciences Edition
基金
泰州师范高等专科学校重点课题(2010-ASL-09)