摘要
本文介绍了以丙酮酸和无水甲醇为原料,加入合适的催化剂合成丙酮酸甲酯的过程。通过对反应物配比、带水剂、反应时间等影响因素进行对比试验,确定以四氯化碳为带水剂,最佳反应配比为:丙酮酸∶无水甲醇∶四氯化碳=1∶2.5∶0.28,产物收率可达73.9%。该工艺过程简单,易操作,适合工业化大生产。
Methyl pyruvate was synthesized by adding to a suitable catalyst with pyruvic acid and absolute methanol. Through changing the factors of influence such as the mix of reactants, different catalyst, and the time of reaction etc. The result showed that the dehydrating agent is carbon tetrachloride, pyruvic acid ： absolute methanol ： carbon tetrachloride = 1： 2.5： 0.28, the yield is 73.9%. The process is simple, operating easily and is fitted to commercial production.
出处
《化学工程师》
CAS
2007年第2期48-50,共3页
Chemical Engineer
关键词
丙酮酸甲酯
丙酮酸
甲醇
合成
methyl pyruvate
pyruvic acid
absolute methanol
synthesis
