摘要
在353 K的乙酰胺-尿素-NaBr熔体中,Ni(Ⅱ)一步不可逆还原为金属Ni,测得在Pt电极上α为0.21和D0为1.15×10-8cm2.s-1;Cu电极上α为0.18和D0为1.44×10-6cm2.s-1.Tb(Ⅲ)和Mg(Ⅱ)不能单独还原为Tb和Mg,但是可以被Ni(Ⅱ)诱导共沉积.由恒电位电解法得到非晶态的Tb-Mg-Ni合金膜.合金中Tb的含量随着阴极电势的负移先增大而后减小,随Tb(Ⅲ)/Ni(Ⅱ)摩尔比增大而增大,Tb的最大含量可达87.88%;Mg的含量随着阴极电势的负移而增大,最大可达12.78%,在Tb(Ⅲ)/Ni(Ⅱ))摩尔比为3.4/1,Mg(Ⅱ)/Ni(Ⅱ)摩尔比为8/1时,Mg/Ni原子比为2/1,符合Mg2Ni储氢合金的组成.
Ni（Ⅱ） was reduced to Ni atom irreversibly by a one-step reaction in acetamide-urea-NaBr melt at 353 K. The determined a is 0.21 on Pt electrode and 0.18 on Cu electrode. The determined Do is 1.15 ×10^-8cm^2·s^-1 on Pt electrode and 1.44× 10^-6 c^2·s^-1 on Cu electrode. Although Tb（Ⅲ）and Mg（Ⅱ） can not be reduced to Tb and Mg alone, they can be inductively codeposited with Ni（Ⅱ） to obtain an amorphous Tb-Mg- Ni alloy film by potentiostatic electrolysis. The content of Terbium in the alloy increases with the increasing of the molar ratio of Tb（Ⅲ）/Ni（Ⅱ） and the maximum is 87.88%. The content of magnesium in the alloy increases with the increasing of the cathodal potential and the maximum was 12.78%. Mg2Ni hydrogen storage alloy was obtained when the molar ratio of Tb（Ⅲ）/Ni（Ⅱ）and Mg（Ⅱ）/Ni（Ⅱ）are 3.4/1 and 8/1.
出处
《山东大学学报（工学版）》
CAS
2006年第6期111-115,120,共6页
Journal of Shandong University（Engineering Science）
基金
国家自然科学基金资助项目(50264004)
教育部重点科学技术研究项目资助(03136)
