摘要
文章根据CDMA系统多用户干扰产生原理导出小区上下行链路用户速率为Rb时的最大用户数公式,据此公式可求出WCDMA、cdma2000和TD-SCDMA标准能提供的小区上下行链路最大用户数,接着导出小区上下行链路可以提供的最大速率Rbmax。文章结果证明只有采用TDMA方式的cdma20001xEV-DO或EDGE方式才能提供合理的高速无线接入Rb。
Basing on the principle of multiuser interference in CDMA systems, this paper presents the formulas of cell capacity on downlink and uplink. Employing these formulas, the cell capacity of WCDMA, cdma2000 and TD-SCDMA on downlink and uplink can be figured out and Rbmax-the maximum date rate provided by these standards on downlink and uplink can also be derived from the cell capacity given above. The conclusion of this paper shows that only cdma2000 lx EV-DO or EDGE, which adopt TDMA method, can provide high speed wireless access Rb.
出处
《电信快报》
2005年第9期5-9,共5页
Telecommunications Information
