摘要
在有关研究工作中涉及到一族复杂函数，其通式为其中ｎ为非负整数，ａｎ＝（ｎ＋１）ｎ＋１／（ｎ＋２）ｎ＋１，经有关计算可得下述定积分计算结果：
Given a family of complicated functions,the general expression of which is asfollows: fn(x)=exp Where n is the nonnegative integer and an=(n+1)n+1/(n+1)n+1,tne definite integral of xn+1 fn(x)has been calculated as followes :
基金
国家自然科学基金
关键词
定积分
函数族
复杂函数
definite integral, function family
