摘要
本文证明了Ｌ［ｙ］＝Ｐｍ（ｘ）ｅａｘ，当ａ不是Ｌ［ｙ］＝０的特征根，则特解必为形如ｙ＝Ｑｍ（ｘ）ｅａｘ的形式；当ａ是Ｌ［ｙ］＝０的ｌ重特征根，则Ｌ［ｙ］＝Ｐｍ（ｘ）ｅａｘ的特解必为ｙ＝ｘｌＱｍ（ｘ）ｅａｘ的形式．解决了该部分在教学中被忽略而使学生产生疑点的问题．
Abstract This article proves that when a is not the characteristic root of L=0 , the particular solution of L=P m(x) e ax must be the form of y=Q m(x) e ax , and when a is the l -ply characteristic root of L =0, the particular solution must be the form y=x 1Q m(x) e ax , and thus solves the problem which is often neglected in teaching and causes questionable point to the students.
出处
《工科数学》
1998年第1期171-173,共3页
Journal of Mathematics For Technology
