摘要
对建立的人工湿地数学模型在两种情况下进行了计算和讨论.在一级反应情况下ci<<km,米氏方程可以简化为r(ci)=-rmax/kmci,使用拉普拉斯变换对模型进行了求解及分析;在零级反应情况下ci<<km,米氏方程可以简为r(ci)=-rmax,使用分离变量法对模型进行计算;从而得到不同情况下,给出初值及边值污染物的相对浓度,为提高人工湿地污水处理提供了有力的理论依据.
This paper makes calculation and discussion on man-made wetland mathematical model under twoconditions, under first order reaction ci〈〈km,Michaelis equation can be simplified into r（ci）=rmax/kmci,uses Laplaceconvert to solve and analyze the model, under zero order reaction ci〉〉km, Michaelis equation can be simplified into r（ci ） = -rmax ,uses separation variable to make calculation on the model, and obtains relative concentration of pol- lutants of initial value and border value under different conditions, providing theoretical basis for sewage treatment of man-made wetland.
出处
《重庆工商大学学报（自然科学版）》
2009年第4期330-333,336,共5页
Journal of Chongqing Technology and Business University:Natural Science Edition
关键词
人工湿地
拉普拉斯变化
分离变量法
man-made wetland
Laplace transform
separating variables method
